One mole of an ideal gas at $25^{o}$ C expands in volume from $1.0$ L to $4.0$ L at constant temperature. What work (in J) is done if the gas expands against vaccum $(P_{e x t e r n a l} = 0)$ ?

- 4.0 \times 10^{2}

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- 3.0 \times 10^{2}

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- 1.0 \times 10^{2}

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Zero

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Solution

The correct option is D Zero
$(D)$ = zero
whenever the expansion is against vactum
$P e x t = 0$
So, work done $= - p d v$
$= 0 (4 - 1) = 0$
zero

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One mole of an ideal gas at 25oC expands in volume from 1.0 L to 4.0 L at constant temperature. What work (in J) is done if the gas expands against vaccum (Pexternal=0)?

The correct option is D Zero(D)= zerowhenever the expansion is against vactum P ext=0So, work done =−pdv=0(4−1)=0zero

One mole of an ideal gas at $25^{o}$ C expands in volume from $1.0$ L to $4.0$ L at constant temperature. What work (in J) is done if the gas expands against vaccum $(P_{e x t e r n a l} = 0)$ ?

The correct option is D Zero
$(D)$ = zero
whenever the expansion is against vactum
$P e x t = 0$
So, work done $= - p d v$
$= 0 (4 - 1) = 0$
zero