Question

One mole of an ideal gas at $300K$ is expanded isothermally from an initial volume of $1litre$ to $10litres$. The value of $\Delta E$ for this process is ($R=2calmo{l}^{-1}{K}^{-1}$)

• A. $163.7cal$
• B. zero
• C. $138.1cal$
• D. $9litreatm$

Answer 1

The correct option is B zero

$\Delta E=n{C}_v\Delta T$

For isothermal process, $\Delta T=0$

Hence, change in internal energy $\left(\Delta E\right)$ is zero during isothermal expansion of a gas.