One mole of an ideal gas [Cv,m=52R] at 300 K and 5 atm is expanded adiabatically to a final pressure of 2 atm against a constant pressure of 2 atm. The final temperature (in Kelvin) of the gas is:
A
270.2
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B
273.0
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C
248.5
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D
200.5
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Solution
The correct option is B248.5 Since the process is an adiabatic processs, q=0 and hence, ΔU=w
nCv,m(T2−T1)=−Pext[nRT2P2−nRT1P1]
For one mole, we have Cv,m(T2−T1)=PextR[T1P1−T2P2]
52R(T2−300)=2×R[3005−T22]⟹T2≈248.5K
Hence, the final temperature of the gas is 248.5K.