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Ideal Gas Equation

One mole of a...

Question

One mole of an ideal gas expands reversibly and adiabatically from a temperature of $27 C$ . If the work done during the process is 3 kJ, then final temperature of the gas is: $(C_{V} = 20 J / K)$
(a) 100 K (b) 150 K
(c) 195 K (d) 255 K

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Solution

The correct option is b
in short Explanation;
$W = n C_{v} (T_{1} - T_{2})$ 0r $T_{1} - T_{2} = \frac{w}{n C_{v}}$
$T_{2} = T_{1} - \frac{W}{n C_{v}} = 300 - \frac{3000}{1 \times 20} = 15 o K$

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