Question

One mole of an ideal gas is compressed from $500$ $c{m}^3$ against a constant pressure of $1.216\times {10}^3$ Pa. The work involved in the process is $35.50J$. Calculate the final volume.

Answer 1

Let final volume 6e V

$P\Delta V=\Delta W$

$P(V_f-V_i)=\Delta W$

$1.216\times {10}^3(V-500)\times {10}^{-3}=35.50$ Joule

$V-500=\frac{35.50}{1.216}=29.194$

$V=529.194c{m}^3$