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Question

One mole of an ideal gas is contained within a cylinder by a frictionless piston and is initially at temperature T. The pressure of the gas is kept constant while it is heated and its volume doubles. If R is molar gas constant, the work done by the gas in increasing its volume is ..............RT.

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Solution

Ideal gas equation PV=nRT

Initial position: PV=RT as mole of gas is one,

Final position: P2V=2RT as volume doubles & P is constant.

So the work done by the gas in increasing its volume is:

W=PV=P2V2P1V1=2RTRT=1×RT.

The correct answer is 1.

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