Question

One mole of an ideal gas is subjected to a two step reversible process ($A-B$ and $B-C$). The pressure at $A$ and $C$ is same. Mark the correct option(s):

• A. Work involved in the path $AB$ is zero
• B. In the path $AB$ work will be done on the gas by the surrounding
• C. Volume of gas at C-3 $\times$ volume of gas at A
• D. Volume of gas at B is $16.42$ litres

Answer 1

Answer: (C), (D)

The correct options are
C Volume of gas at C-3 $\times$ volume of gas at A
D Volume of gas at B is $16.42$ litres

According to ideal gas equation
At point B:

$PV=nRT;V=\frac{1\times 0.082\times 600}{3}=16.42$ lit

Also as pressure is same at A and C so

$\frac{V_C}{V_A}=\frac{T_C}{T_A}=\frac{3}{1}$

$\Rightarrow V_C=3\times V_A$