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PV Work

One mole of a...

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One mole of an ideal gas is taken from a to b along two paths denoted by the solid and the dashed lines as shown in the graph below. It the work done along the solid line path is $W_{s}$ and that along the dotted line path is $\frac{W_{d}}{W_{s}}$ is ___

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Solution

Work done along dashed path $| - W | = \sum P Δ V$
$= 4 \times 1.5 + 1 \times 1 + \frac{2}{3} \times 2.5 = 8.65 L a t m$
Work done along solid path - $W = n R T l n \frac{V_{2}}{V_{1}} = p_{1} V_{1} l n \frac{V_{2}}{V_{1}}$
$= 2 \times 2.3 l o g \frac{5.5}{0.5} = 2 \times 2.3 l o g 11 = 4.79 \Rightarrow \frac{W_{d}}{W_{s}} = \frac{8.65}{4.79} = 1.80 \approx 2$

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Q. One mole of an ideal gas is taken from a to b along two paths denoted by the solid and the dashed lines as shown in the graph below. If the work done along the solid line path is

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, then the integer closest to the ratio

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