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Question
One mole of an ideal gas (γ=1.4) is adiabatically compressed so that its temperature rises from 27oC to 35oC. The work done by the gas is
(R= 8.47J/mol/K)
One mole of an ideal gas (γ=1.4) is adiabatically compressed so that its temperature rises from 27oC to 35oC. The work done by the gas is
(R= 8.47J/mol/K)
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Solution
The correct option is B −169.4J
Heat-Work relation is
dQ=dU+dW
For an adiabatic process dq=0;
dW=−dU=−nCvΔT=−(1)(5R2)(35−27)=−2.5(8.47)(8)=−169.4J
Heat-Work relation is
dQ=dU+dW
For an adiabatic process dq=0;
dW=−dU=−nCvΔT=−(1)(5R2)(35−27)=−2.5(8.47)(8)=−169.4J
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