Question

One mole of an ideal gas undergoes a cyclic process ABCDA as shown in the P-V diagram, The net work done in the process is:
(1 atm =${10}^6$ dyne ${cm}^{-2}$)

• A. 500 J
• B. 700 J
• C. 800 J
• D. 900 J

Answer 1

Answer: (C)

800 J

From the P-V diagram,

Work done, $W=areaundertheP-Vdiagram$

$W=AB\times BC$

$W=2litre\times 4atm$

$W=2\times {10}^{-3}\times 4\times 1.03\times {10}^5$

$W=8\times 100$

$W=800J$

The correct option is C.