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Byju's Answer
Standard XII
Chemistry
Compressibility Factor
One mole of a...
Question
One mole of an ideal gas undergoes a process
P
=
P
0
(
1
+
(
2
V
0
V
)
2
]
−
1
,
where
P
0
,
V
0
are constants. Change in temperature of the gas when volume is changed from
V
=
V
0
to
V
=
2
V
0
is
n
P
o
V
0
R
. Then
n
is
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Solution
P
=
P
0
(
1
+
(
2
V
0
V
)
2
]
−
1
A
t
V
=
V
0
,
P
=
P
0
5
T
i
=
P
V
n
R
=
(
P
0
5
)
V
0
n
R
=
P
0
V
0
5
n
R
A
t
V
=
2
V
0
,
P
=
P
0
2
T
f
=
P
V
n
R
=
(
P
0
2
)
2
V
0
n
R
=
P
0
V
0
n
R
Δ
T
=
T
f
−
T
i
=
4
P
0
V
0
5
n
R
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