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Question

One mole of an ideal gas undergoes a process  P = P0 (1 + (2V0V)2]1,where P0, V0  are constants. Change in temperature of the gas when volume is changed from V=V0to V=2V0 is nPoV0R. Then n is 


Solution

P = P0 (1 + (2V0V)2]1At V = V0, P =  P05Ti = PVnR = (P05)V0nR = P0V05nRAt V = 2V0, P =  P02Tf= PVnR = (P02)2V0nR = P0V0nRΔT = Tf  Ti = 4P0V05nR

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