One mole of an Ideal gas was compressed isothermally and reversibly from 22.4×10−3m3 and one atmospheric pressure to 11.2×10−3m3(R=8.314J/K/mol). The work done on the system is
A
- 1134 J
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B
1134 J
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C
1573 J
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D
Cannot be caluclated
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Solution
The correct option is C1573 J Since 1 mole of an Ideal gas at 1 atmosphere was taken and since initial volume was 22.4dm3, the temperature must be 273 K. (Molar volume of an ideal gas at STP is 22.4dm3) W=−2.303nRTlog(V2V1)=−2.303nRTlog(11.2×10−322.4×10−3)=−2.303nRTlog(0.5)=−2.303×1mol×8.314J/K/mol×273K×(−0.3010)W=+1573J