One mole of an ideal monatomic gas at temperature T0 expands slowly according to the law PV= constant. If the final temperature is 2T0, heat supplied to the gas is?
A
2RT0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
RT0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
32RT0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12RT0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A2RT0 In a process PVx=constant, molar heat capacity is given by C=Rγ+1+R1−x As the process is PV= constant, i.e., PV−1=constant, therefore, x=−1. For an ideal monatomic gas, γ=53 ∴C=R53−1+R1−(−1)=32R+R2=2R ΔQ=nC(ΔT)=1(2R)(2T0−T0)=2RT0