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Question

One mole of an ideal mono-atomic gas is subjected to a cyclic process connecting the states L,M and N as shown in the pressure - temperature diagram given below. The line LM passes through the origin, while MN and LN are parallel to the pressure and temperature axes respectively.
The correct statements is : (R is the universal gas constant).

884989_4991dfc897364924815c98249a348bf6.jpg

A
Work done along the path LM is 300R
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B
Work done along the path NL is 750R
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C
Work done along the path LM is zero
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D
Enthalpy change along the path MN is greater than zero
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Solution

The correct option is D Work done along the path LM is zero
The LM is a straight line which is uniformly increasing for PT curve. Therefore, LM is a constant volume process.
ΔV=0forLM
It is an isochoric process.
Work done along the path LM=PΔV=0

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