Question

One mole of an ideal monoatomic gas is caused to go through the cycle shownin figure. Then the change in the internal energy in expending the gas from a to c along the path abc is :

• A. ${3P}_0{V}_0$
• B. ${6RT}_0$
• C. ${4.5RT}_0$
• D. ${10.5RT}_0$

Answer 1

The correct option is D ${10.5RT}_0$

Temperature at 'a'= $T_0=\frac{PV}{R}$
At $\left(a\right)T_0=\frac{P_0{V}_0}{R}.......\left(i\right)$
At $\left(c\right)T_c=\frac{{(2P}_0\left){(4V}_0\right)}{R}{8T}_0$
$\Delta U={nC}_v(T_f-T_i)=\frac{3}{2}R({8T}_0-T_o)$
$\Delta U=\frac{{21RT}_0}{2}={10.5RT}_0$