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Question

One mole of an ideal monoatomic gas undergoes a process as shown in the figure. Find the molar specific heat of the gas in the process (R is a gas constant).

A
3R4
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B
R2
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C
R3
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D
2R3
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Solution

The correct option is B R2
V = m(1T); m = slope of the curveVT = Constant; TdV + VdT = 0dV = −VTdT (1)Q = ΔU + WCdT = CvdT + PdV
From equation (1)
CdT = CvdT − PTVdT ⇒ C = Cv − PVTFor monoatomic gas Cv = 32RC = Cv−R = 32R−R⇒C=R2

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