One mole of an ideal monoatomic gas undergoes a process as shown in the figure. Find the molar specific heat of the gas in the process (R is a gas constant).
A
3R4
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B
R2
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C
R3
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D
2R3
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Solution
The correct option is BR2 V=m(1T);m=slopeofthecurveVT=Constant;TdV+VdT=0dV=−VTdT(1)Q=ΔU+WCdT=CvdT+PdV
From equation (1) CdT=CvdT−PTVdT⇒C=Cv−PVTFormonoatomicgasCv=32RC=Cv−R=32R−R⇒C=R2