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Gay Lussac's Law, Avagadro's Law

One mole of a...

Question

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in $100$ mL of $0.02$ M $H_{2} S O_{4}$ solution is __________?

12.044 \times 10^{20}

molecules

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6.022 \times 10^{23}

molecules

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1 \times 10^{23}

molecules

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12.044 \times 10^{23}

molecules

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Solution

The correct option is C $12.044 \times 10^{20}$ molecules
Moles of $H_{2} S O_{4} =$ Molarity of $H_{2} S O_{4} \times$ Volume of solution $(L)$

$= 0.02 \times 0.1$

$= 2 \times 10^{- 3}$ moles

No. of $H_{2} S O_{4}$ molecules $= 2 \times 10^{- 3} \times 6.022 \times 10^{23} = 12.044 \times 10^{20}$ molecules

Therefore, the correct option is A.

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Similar questions

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of $0.02 M H_{2} S O_{4}$ solution is.............

(a) $12.044 \times 10^{20}$ molecules (b) $6.022 \times 10^{23}$ molecules

Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more,

6.022 \times 10^{23}

molecules of

C O_{2}

6.022 \times 10^{23}

molecules of

H_{2} O

If 32 g of $O_{2}$ contains 6.022 $\times 10^{23}$ molecules at NTP then 32 g of S, under the same conditions, will contain,

Q. Anushka, Karuna, Sohan and Krishna having a container with 6 moles of F atoms, 6 moles of

F_{2}

molecules,

12.044 \times 10^{23}

number of F atoms and

6.022 \times 10^{23}

number of

F_{2}

molecules respectively.
Which among the four will have the same amount of F atoms in grams?

Q. Calculate the number of

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One mole of any substance contains 6.022×1023 atoms/molecules. Number of molecules of H2SO4 present in 100mL of 0.02M H2SO4 solution is __________?

The correct option is C 12.044×1020 moleculesMoles of H2SO4= Molarity of H2SO4× Volume of solution (L)=0.02×0.1=2×10−3 molesNo. of H2SO4 molecules =2×10−3×6.022×1023=12.044×1020 moleculesTherefore, the correct option is A.

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in $100$ mL of $0.02$ M $H_{2} S O_{4}$ solution is __________?