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Standard X

Chemistry

Mole Concept and Avogadro's Number

One mole of a...

Question

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of 0.02 M $H_{2} S O_{4}$ solution is ________ molecules.

12.044 \times 10^{20}

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6.022 \times 10^{23}

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1 \times 10^{23}

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12.044 \times 10^{23}

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Solution

The correct option is A $12.044 \times 10^{20}$
Number of moles of $H_{2} S O_{4} =$ Molarity $\times$ Volume (Litres) $= 0.02 \times 0.1 = 2 \times 10^{- 3}$ $m o l e s$
Number of molecules $= 2 \times 10^{- 3} \times 6.022 \times 10^{23} = 12.044 \times 10^{20}$ molecules

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Similar questions

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of $0.02 M H_{2} S O_{4}$ solution is.............

(a) $12.044 \times 10^{20}$ molecules (b) $6.022 \times 10^{23}$ molecules

Q. 12 g C-12 contains

6.022 \times 10^{23}

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6.022 \times 10^{23}

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If 32 g of $O_{2}$ contains 6.022 $\times 10^{23}$ molecules at NTP then 32 g of S, under the same conditions, will contain,

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One mole of any substance contains 6.022×1023 atoms/molecules. Number of molecules of H2SO4 present in 100 mL of 0.02 M H2SO4 solution is ________ molecules.

The correct option is A 12.044×1020Number of moles of H2SO4= Molarity × Volume (Litres) =0.02×0.1=2×10−3 molesNumber of molecules =2×10−3×6.022×1023=12.044×1020 molecules

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of 0.02 M $H_{2} S O_{4}$ solution is ________ molecules.

The correct option is A $12.044 \times 10^{20}$
Number of moles of $H_{2} S O_{4} =$ Molarity $\times$ Volume (Litres) $= 0.02 \times 0.1 = 2 \times 10^{- 3}$ $m o l e s$
Number of molecules $= 2 \times 10^{- 3} \times 6.022 \times 10^{23} = 12.044 \times 10^{20}$ molecules