Question

One mole of chlorine combines with certain weight of metal giving 111 g of its chloride (formula :$MC{l}_2$). The same amount of metal can displace 2 g hydrogen from an acid. The equivalent weight of metal is:

• A. 40
• B. 20
• C. 80
• D. 10

Answer 1

The correct option is B 20

One mole of chlorine $=$ $71$ g.

Molecular weight of $MC{l}_2=111g$

$M+71=111$

$M=111-71=40$

$2g$ of $H_2$ is displaced by $40g$ of metal, then $1$ g of $H_2$ is displaced by $\frac{40}{2}=20$ g of the metal.