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Common Ion Effect

One mole of ...

Question

One mole of $C o C l_{3} \cdot 4 N H_{3}$ on reaction with excess of $A g N O_{3}$ gives one mole of white precipitate that is $[C o (N H_{3})_{4} C l_{2}] C l$ .
If true enter 1, else enter 0.

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Solution

One mole of $C o C l_{3} \cdot 4 N H_{3}$ on reaction with excess of $A g N O_{3}$ gives one mole of white precipitate which means the complex exists as $[C o (N H_{3})_{4} C l_{2}] C l$ .
The formation of white precipitate is due to the reaction of $A g N O_{3}$ wth $C l^{-}$ giving $A g C l$ . One mole of AgCl is obtained means only one $C l$ is free. Hence, the complex has to be $[C o (N H_{3})_{4} C l_{2}] C l$ .
Therefore, the statement is true.

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