Question

One mole of complex compound $Co(N{H}_3{)}_{5}C{l}_3$ gives 3 moles of ions in dissolution in water. One mole of the same complex reacts with two moles of $AgN{O}_3$ to yield two moles of $AgC{l}_{\left(s\right)}$. The complex is :

• A. $\left[Co\right(N{H}_3{)}_{4}C{l}_2]Cl.N{H}_3$
• B. $\left[Co\right(N{H}_3{)}_{4}Cl]C{l}_2.N{H}_3$
• C. $\left[Co\right(N{H}_3{)}_{5}Cl]C{l}_2$
• D. $\left[Co\right(N{H}_3{)}_{3}C{l}_3].2N{H}_3$

Answer 1

The correct option is C $\left[Co\right(N{H}_3{)}_{5}Cl]C{l}_2$

$\left[Co\right(N{H}_3{)}_{5}Cl]C{l}_2+AgN{O}_3⟶[Co\left(N{H}_3{)}_{5}Cl\right](N{O}_3{)}_2+AgC{l}_2$

The complex is $\left[Co\right(N{H}_3{)}_{5}Cl]C{l}_2$.

Option (C) is correct.