Question

One mole of $P_2{O}_5$ undergoes hydrolysis as

$P_2{O}_5+H_{2}O⟶H_3{PO}_4$

The normality of the phosphoric acid formed is (The volume of solution is 1 L)

• A. 2
• B. 12
• C. 24
• D. 4

Answer 1

The correct option is B 12

$\underset{1mol}{P_2{O}_5}+6H_{2}O⟶4\underset{4mol}{H_3{PO}_4}$

$\therefore$ 1 L solution contains 4 mol $H_3{PO}_4$

$\therefore$ Molarity of $H_3{PO}_4=4M$

Normality = Molarity x Basicity

$=4\times 3N=12N$

So, the correct option is $B$