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Heat Capacity

One mole of e...

Question

One mole of ethane was burnt in oxygen at constant volume to give $C O_{2}$ at 298 K. The heat evolved was found to be 1554 kJ. Calculate the heat of reaction at constant pressure.

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Solution

$H = 1554$ $k j$ $T = 298 K$
$C_{2} H_{6} + \frac{7}{2} O_{2} ⟶ 2 C O_{2} + 3 H_{2} O$
$△ n g = (\frac{9}{2} - 2) = \frac{5}{2}$
$△ H = △ U + △ n_{g} R T △ H = 1334 - \frac{5}{2} (8.3) (298) △ H = 1554 - 6183 = - 4629.5 kj$

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