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One mole of G...

Question

One mole of Gas in a 10 litre vessel exerts a pressure of 185.6 cm of Hg at $25^{\circ}$ C. Calculate the value of ‘a’.
Given R = .0821 litre/degree mole and b = 0.0391 litre/mole.

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Solution

The correct option is A
According to vanderwaal’s equation, for one mole of gas.
$(P + \frac{a}{V^{2}}) (V - b) = R T$
$\Rightarrow (P + \frac{a}{V^{2}}) = \frac{R T}{V - b}$
$\Rightarrow \frac{a}{V^{2}} = \frac{R T}{V - b} - P o r, a = (\frac{R T}{V - b} - P) V^{2}$
or, $a = (\frac{.0821 \times 298}{10 - 0.0391} - \frac{185.6}{76}) \times (10)^{2}$
or, $a = 0.76 L^{2} a t m / m o l$

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