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Question

# One mole of Helium gas undergoes a reversible cyclic process ABCDA as shown in the figure. Assuming gas to the ideal, answer the following questions: What is the value of ‘q’ for the overall cyclic process?

A
100R ln 2
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B
+100R ln 2
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C
+200R ln 2
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D
200R ln 2
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Solution

## The correct option is B +100R ln 2AB, CD : isothermal; BC, DA : isobaric. ∴qAB=−ωAB=1×R×300ln(12)=−300Rln2 [as,ω=−nRTln(P1P2)] qBC=nCP△T=1×52R×100=250R qCD=−ωCD=1×R×400ln(2/1)=400Rln2 qDA=nCp△T=1×52R×−100=250R ∴ qtotal=100 Rln 2

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