Question

One mole of $HN{O}_3$ absorbs $4$ mol of electrons in a redox reaction. The reduced product of this reaction is :

• A. $\frac{1}{2}$ mol $N_2$
• B. $\frac{1}{2}$ mol $N_{2}O$
• C. $1$ mol $N{O}_2$
• D. $1$ mol $N{H}_3$

Answer 1

The correct option is B $\frac{1}{2}$ mol $N_{2}O$

The oxidation number of $N$ in $HN{O}_3$ is $+5$.
On absorption of $4$ moles of electrons, the oxidation number decreases to $+1$.
The oxidation number of $N$ is $N_{2}O$ is $+1$.
One mole of $HN{O}_3$ absorbs $4$ mol of electrons in a redox reaction.
The reduced product of this reaction is $\frac{1}{2}$ mol $N_{2}O$.