Question

One mole of ideal gas at $300K$ is expanded isothermal from an initial volume of $1$ litre to $10$ litre. The $\Delta E$ (internal energy) for the process is: $(R=2cal{K}^{-1}{mol}^{-1})$

• A. $163.7$ cal
• B. $1381.1$ cal
• C. $9$ litre-atm
• D. zero

Answer 1

The correct option is D zero

$n=1$ mole

$T=300$ K

$V_1=1$ litre

$V_2=10$ litres

$R=2cal{K}^{-1}{mol}^{-1}$

For isothermal process, $\Delta E=n{C}_V\Delta T$

$=n\times C_V\times 0$

$\Delta E=0$