Question

One mole of iron $\left[55.8gm\right]\left[55.8gm\right]$ oxidation state gives up:

• A. $1N_A$ electron
• B. $2N_A$ electron
• C. $3N_A$ electron
• D. $0.5$ mole of electron

Answer 1

The correct option is B $2N_A$ electron

Solution $-$

No. of moles $=\frac{No.ofentities}{N_A.}$

$1$ mole $\times N_A=$ No. of entities

Therefore $1Mole=55.8gm=N_A$

The oxidation state of iron (Fe)

$\Rightarrow +2$

Hence, 1 mole of iron $\left[55.8gm\right]$

oxidation state gives up

$2N_{A}electron$