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Question

One mole of N2 is mixed with three mole of H2 in a 4 litre vessel. If 0.25% N2 is converted into NH3 by the reaction :

N2(g)+3H2(g)2NH3(g). Kc for (1/2)N2+(3/2)H2NH3 is x×103 L mol1.

What is the value of x to the nearest integer?

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Solution

The degree of dissociation is 0.25% or 0.0025.

N2
H2
NH3
Initial number of moles
1
3
0
Equilibrium number of moles
10.0025=0.9975
30.0075=2.9925
0.0050
The equilibrium constant expression for the reaction N2(g)+3H2(g)2NH3(g) is Kc=[NH3]2[N2][H2]3=(0.00504)2(0.99754)(2.99254)3=(0.00125)2(0.249375)(0.748125)3=1.496×105 .
The equilibrium constant for the reaction (1/2)N2+(3/2)H2NH3 is KC=1.496×105=3.868×103L mol1=x×103L mol1.
Hence, x=3.868

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