One mole of NaCl(s) on melting absorved 30.5 kJ of heat and its entropy is increased by $28.8 J K^{1}$ . What is the melting point of sodium chloride?

T = 1059 k

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T = 10.59 k

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T = 105.9 k

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None of these

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Solution

The correct option is D $T = 1059 k$
The entropy change for the process is $Δ S = 28.8 J / K$
The enthalpy change for the process is $Δ H = 30.5 k J$
The relationship between the enthalpy change and the entropy change is

$Δ H = T Δ S$ or $T = \frac{Δ H}{Δ S}$
Substitute values in the above expression.
$T = \frac{30.5 \times 10^{3}}{28.8} = 1059 K$
Hence, the melting point of NaCl is 1059 K.

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One mole of NaCl(s) on melting absorved 30.5 kJ of heat and its entropy is increased by 28.8JK1. What is the melting point of sodium chloride?

One mole of NaCl(s) on melting absorved 30.5 kJ of heat and its entropy is increased by $28.8 J K^{1}$ . What is the melting point of sodium chloride?