Question

One mole of non-ideal gas undergoes a change of state (1.0 atm, 3.0 L, 200 K) to (4.0 atm, 5.0 L, 250 K) with a change in internal energy $\Delta U$ = 40 L-atm. The change in enthalpy of the process in L-atm is :

• A. 43
• B. 57
• C. 42
• D. None of these

Answer 1

The correct option is B 57

When both P and V are changing,
$\Delta H=\Delta U+\Delta \left(PV\right)=\Delta U+(P_2{V}_2-P_1{V}_1)=40+(20-3)=57Latm$