Question

One mole of $O_2$ gas having a volume equal to $22.4$ litres at $0^{\circ }C$ and 1 atmospheric pressure is compressed isothermally so that its volume reduces to $11.2$ litres. The work done in this process is

• A. $1672.5\text{J}$
• B. $1728\text{J}$
• C. $-1728\text{J}$
• D. $-1572.5\text{J}$

Answer 1

The correct option is D $-1572.5\text{J}$


Work done during isothermal process,
$W.D=nRT\ln \frac{V_2}{V_1}$
$n=1\text{mole}T=273\text{K}$
$⟹W.D=8.314\times 273(-0.693)$
$=-1572.5J$