One mole of oxygen gas at STP is equal to_____.

6.022 \times 10^{23}

molecules of oxygen

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6.022 \times 10^{23}

atoms of oxygen

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16 g

of oxygen.

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32 g

of oxygen.

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Solution

Step 1:
1 mole of $O_{2}$ gas at STP = $6.022 \times 10^{23}$ molecules of $O_{2}$ (Avogadro’s number)
1 mole of $O_{2}$ gas at STP = $32 g$ of $O_{2}$
Step 2:
Molecular weight of oxygen = $2 \times 16 = 32$
Hence, 1 mole of oxygen gas is equal to the molar weight of oxygen gas as well as the Avogadro’s number.
Hence, options (A) and (D) are correct.

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