Question

One mole of oxygen is allowed to expand isothermally and reversibly from $5m^3$ to $10m^3$ at 300 K. Calculate the work done in expansion of the gas.

Answer 1

The work done $W=-2.303nRTlo{g}_{10}\frac{V_2}{V_1}$

$W=-2.303\times \text{1 mol}\times \text{8.314 J/mol/K}\times \text{300 K}\times lo{g}_{10}\frac{{\text{10 m}}^3}{{\text{5 m}}^3}$

$W=-\text{1729 J}$

The work done in the expansion of the gas is $-\text{1729 J}$.