Question

One mole of oxygen of volume 1 litre at 4 atm pressure to attain 1 atm pressure by result of isothermal expansion. Find work done by the gas.

• A. $\sim 155J$
• B. $\sim 206J$
• C. $\sim 355J$
• D. $\sim 562J$

Answer 1

The correct option is D $\sim 562J$

In isothermal process,

$\omega =2303RT{\log }_{10}\left(\frac{P_1}{P_2}\right)$

Also, $PV=nRT$

$\Rightarrow \left(\frac{PV}{n}\right)=RT$

So, $\omega =\left(2.303\right)\left(\frac{PV}{n}\right){\log }_{10}\left(\frac{P_1}{P_2}\right)$

Here,

$\omega =\left(2.303\right)\left(\frac{4\times 1}{1}\right){\log }_{10}\left(\frac{4}{1}\right)\times 100J$

$=\left(2.303\right)\left(4\right)\times \left(0.602\right)\times 100J$

$=546J\approx 562J$

Option $D$ is correct