1 mole of $H_{2}$ $O_{2}$ had been prepared by the electrolysis of 50% $H_{2}$ $S O_{4}$ ,followed by hydrolysis.Calculate the number of moles of electrons involved in this process.

Q. The number of electrons involved in the manufacture of 1 mole of

H_{2} O_{2}

from 50%

H_{2} S O_{4}

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One mole of PbS is oxidised to PbSO4 by H2O2. In this process, the number of electrons involved are [N0 = Avagadro number]

The correct option is D 8N0 From PbS to PbSO4 the oxidation state changes from -2 to + 6

One mole of PbS is oxidised to $P b S O_{4}$ by $H_{2}$ $O_{2}$ . In this process, the number of electrons involved are [ $N_{0}$ = Avagadro number]

The correct option is D
8N₀

From PbS to $P b S O_{4}$ the oxidation state changes from -2 to + 6