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Chlorination

One mole ofph...

Question

One mole of photons is known as one Einstein of radiation. According to Stark-Einstein law of photochemical equivalence, one mole of reactant absorbs one Einstien of energy. For a photochemical reaction, a term called quantum yield is defined as:
Quantum yield $(ϕ) = \frac{N o . o f m o l e s o f r e a c t a n t c o n v e r t e d}{N o . o f E i n s t e i n a b s o r b e d}$
The correct statement(s) is/are:

for a chain reaction

ϕ_{g a s} >> ϕ_{s o l u t i o n}

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in a photochemical chain reaction

ϕ >> 1

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in a photochemical chain reaction

ϕ << 1

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for a chain reaction

ϕ_{g a s} << ϕ_{s o l u t i o n}

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Solution

The correct options are
A for a chain reaction $ϕ_{g a s} >> ϕ_{s o l u t i o n}$
B in a photochemical chain reaction $ϕ >> 1$
$Q u a n t u m Y i e l d = \frac{N u m b e r o f m o l e s o f r e a c t a n t c o n v e r t e d}{N u m b e r o f e i n s t e i n a b s o r b e d}$
An einstein of radiation $=$ one mole of photons
For a chain reaction, $ϕ_{g a s} >> ϕ_{s o l u t i o n}$
and ln photochemical chain reaction $ϕ >> 1$

Suggest Corrections

Similar questions

(ϕ)

\frac{m o l e s o f t h e s u b s t a n c e r e a c t e d}{m o l e s o f t h e p h o t o n s a b s o r b e d}

{(C H}_{3})_{2} C O

h v - \to

C_{2} H_{6}

10^{- 3}

{J s}^{- 1}

C O

N_{A}

10^{23}

10^{- 34}

C l_{2} (h v) - - \to 2 C l^{∙}

C l^{∙} + H_{2} k_{1} \to H C l + H^{∙}

H^{∙} + C l_{2} k_{2} \to H C l + C l^{∙}

2 C l^{∙} k_{3} \to C l_{2}

H_{2}

C l_{2}, C l_{2}

C l_{2}

H C l

Define:

(a) Photochemical reaction

(b) Electrochemical reaction.

Give one example in each case.

C H_{3} C H O

∙ C H_{3} a n d ∙ C H O

^{'} I_{a b s}^{'}

[∙ C H_{3}] a n d \frac{d [C O]}{d t}

[∙ C H_{3}], [∙ C H_{3} C O]

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