One mole of potassium chlorate is thermally decomposed and excess of aluminium is burnt in the gaseous product. How many moles of aluminium oxide are formed ?

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1.5

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Solution

The correct option is A 1
$2 K C l O_{3} \to 2 K C l + 3 O_{2}$
$4 A l + 3 O_{2} \to 2 A l_{2} O_{3}$ .
The molar ratio for the first reaction is 2:3 for $K C l O_{3} : O_{2}$ . Thus, if 1 mole of $K C l O_{3}$ is decomposed, 1.5 moles of $O_{2}$ is produced.
The molar ratio for the second reaction is: 3:2 for $O_{2} : A l_{2} O_{3}$ . 3 moles of oxygen produces 2 moles of aluminium oxide.
Since, we have 1.5 moles of oxygen, number of moles of $A l_{2} O_{3}$ produced $= 1.5 m o l e s O_{2} \times \frac{2 m o l e s A l_{2} O_{3}}{3 m o l e s O_{2}} = 1 m o l e A l_{2} O_{3}$

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