Question

One mole of the complex $Co(N{H}_3{)}_{5}C{l}_3$ gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with 2 moles of $AgN{O}_3$ to yield 2 moles of $AgC{l}_{\left(s\right)}$. The complex is:

• A. $\left[Co\right(N{H}_3{)}_{4}C{l}_2]Cl.N{H}_3$
• B. $\left[Co\right(N{H}_3{)}_{4}Cl]C{l}_2.N{H}_3$
• C. $\left[Co\right(N{H}_3{)}_{4}Cl]C{l}_2$
• D. $\left[Co\right(N{H}_3{)}_{3}C{l}_3].2N{H}_3$

Answer 1

The correct option is C $\left[Co\right(N{H}_3{)}_{4}Cl]C{l}_2$

The complex is $\left[Co\right(N{H}_3{)}_{5}Cl]C{l}_2$.
$\left[Co\right(N{H}_3{)}_{5}Cl]C{l}_2\to [Co(N{H}_3{)}_{5}Cl{]}^{2+}+2C{l}^{-}$

$\left[Co\right(N{H}_3{)}_{5}Cl]C{l}_2+2AgN{O}_3\to [Co\left(N{H}_3{)}_{5}Cl\right](N{O}_3{)}_2+2AgCl$