Question

One mole of the complex compound $Co(N{H}_3{)}_{5}C{l}_3$, gives $3$ moles of ions on dissolution in water. One mole of the same complex reacts with two moles of $AgN{O}_3$ solution to yield two moles of $AgCl\left(s\right)$. The structure of the complex is

• A. $\left[CO\right(N{H}_3{)}_{3}C{l}_3].2N{H}_3$
• B. $\left[CO\right(N{H}_3{)}_{4}C{l}_2].ClN{H}_3$
• C. $\left[CO\right(N{H}_3{)}_{4}Cl].N{H}_3$
• D. $\left[CO\right(N{H}_3{)}_{5}Cl].C{l}_2$

Answer 1

The correct option is D $\left[CO\right(N{H}_3{)}_{5}Cl].C{l}_2$

The structure of the complex here is $\left[CO\right(N{H}_3{)}_{5}Cl].C{l}_2$
On dissolution in water
$\left[CO\right(N{H}_3{)}_{5}Cl].C{l}_2\rightleftharpoons [CO(N{H}_3{)}_{5}Cl{]}^{+}+2C{l}^{-}$
SO it will give $3$ moles of ions on dissolution.
Now $\left[CO\right(N{H}_3{)}_{5}Cl]C{l}_2+2AgN{O}_3\to [CO\left(N{H}_3{)}_{5}Cl\right](N{O}_3{)}_2+2AgCl$.
So one mole of the complex reacts with two moles of $AgN{O}_3$ solution to yield two moles of $AgCl\left(s\right)$.