Question

One molecule of a binary acid contains two hydrogen atoms and a negative radical X. What will be the formula of the salts when it reacts with bases like $M\left(OH\right),M(OH{)}_2$ and $M(OH{)}_3$? Explain with reasons.

Answer 1

Let the binary acid be $H_{2}X$ , valency of x=2

$H_{2}X+base\to salt$ of X $+H_{2}O$

when base is $M\left(OH\right)$

So, here the valency of M is 1

$M_{2}X$ is the formula of salt.

When base is $M(OH{)}_2$

Valency of M is 2

MX is the formula of salt

When base is $M(OH{)}_3$

Valency of M is 3

$M_2{X}_3$ is the formula of the salt