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Question

One molecule of dialkyl ether produces how many molecules of alkyl halides with excess of halogen acid?

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is B 2
The given reaction will proceeds through SN2 reaction mechanism. Dialkyl ethers when treated with excess halogen acid first forms an alkyl halide and an alcohol. The alcohol further reacts with the excess acid to form the respective alkyl halide and a water molecule. Thus, two alkyl halide molecules are produced in the end.

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