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Volume of Gases and Number of Moles

One normal so...

Question

One normal solution of ${N a}_{2} {C O}_{3}$ contains:

one formula weight per litre

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two formula weight per litre

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half formula weight per litre

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one third (1/3) formula per litre

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Solution

The correct option is C half formula weight per litre
For $N a_{2} C O_{3}$ ,

$E q u i v a l e n t w e i g h t = \frac{formula weight}{2}$
$N o r m a l i t y = \frac{equivalent weight}{1 litre of volume}$
$= \frac{1}{2} \times \frac{formula weight}{1 litre of volume}$
$= half formula weight per litre$

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