One number is 3 less than the two times of the other; if their sum is increased by 7 the result is 37. Find the numbers.

9, 11

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11, 13

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11, 19

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9, 13

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Solution

The correct option is C $11, 19$
Let one number = x
other number = 2x-3
$(x + 2 x - 3) + 7 = 37$
3x = 33
x = 11
$∴$ The two number are 11 and 19

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One number is 3 less than the two times of the other; if their sum is increased by 7 the result is 37. Find the numbers.

The correct option is C 11,19Let one number = xother number = 2x-3 (x+2x−3)+7=373x = 33x = 11∴ The two number are 11 and 19

The correct option is C $11, 19$
Let one number = x
other number = 2x-3
$(x + 2 x - 3) + 7 = 37$
3x = 33
x = 11
$∴$ The two number are 11 and 19