Let A be the event of choosing a number divisible by 4
∴A=4,8,....,100
⇒n(A)=25
P(A)=25100
Let B be the event of choosing a number divisible by 6
∴B=6,12,...,96
⇒n(B)=16
P(B)=16100
(A∩B)=12,24,.....,96
⇒n(A∩B)=8
∴P(A∩B)=8100
∴P(A∪B)=P(A)+P(B)−P(A∩B)
=25100+16100−8100=33100