Question

One number is chosen from numbers 1 to 200. Find the probability that it is divisible by 4 and 6 both.

• A. $\frac{17}{200}$
• B. $\frac{67}{200}$
• C. $\frac{31}{200}$
• D. None of these

Answer 1

The correct option is D None of these

Total numbers divisible by $4$ in between $1$ and $200=50$
Total numbers divisible by $6$ in between $1$ and $200=33$
Now, total numbers which are divisible by both $4$ and $6=8$
Hence, number divisible by either $4$ or $6$ = $50+33-8=75$
Total numbers $=200$
Hence, required probability = $\frac{75}{200}=\frac{3}{8}$