One number is three times another. If the larger number is subtracted from $60$ , the result is $5$ less than the smaller number when subtracted from $55$ . Find the numbers.

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Solution

Let the first number be 'a'
Second number = 3a.
According to question
$60 - 3 a = (55 - a) - 5$
$60 - 3 a = 50 - a .$
$2 a = 10.$
$a = 5$
$∴$ First number = 5
second number = 15

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One number is three times another. If the larger number is subtracted from 60, the result is 5 less than the smaller number when subtracted from 55. Find the numbers.

Let the first number be 'a'Second number = 3a.According to question60−3a=(55−a)−560−3a=50−a.2a=10.a=5∴ First number = 5second number = 15

One number is three times another. If the larger number is subtracted from $60$ , the result is $5$ less than the smaller number when subtracted from $55$ . Find the numbers.

Let the first number be 'a'
Second number = 3a.
According to question
$60 - 3 a = (55 - a) - 5$
$60 - 3 a = 50 - a .$
$2 a = 10.$
$a = 5$
$∴$ First number = 5
second number = 15