Question

One number is to be chosen from 11 to 100, find the probability that the number chosen will be divisible by both 3 and 7___.

• A. 2/45
• B. 1/10
• C. 4/9
• D. 12/100

Answer 1

Answer: (A)

2/45

There are total 90 numbers between 11 and 100

The number which are divided by 3 and 7 then It must be divided by 21

The number which are divided by 21 are 21,42,63,84

Probability=$\frac{4}{90}=\frac{2}{45}$